A $ 10 \, \text{eV} $ electron is circulating in a plane at right angles to a uniform field at magnetic induction $ 10^{-4} \, \text{Wb/m}^2 $ ($ = 1.0 \, \text{gauss} $). The orbital radius of the electron is

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12 cm. The radius of the circular motion of a charged particle in a magnetic field is given by the formula $ r = \frac{mv}{qB} $. Using the kinetic energy $ KE = \frac{1}{2}mv^2 $, we can find $ v = \sqrt{2KE/m} $. Substituting $ KE = 10 \, \text{eV} = 1.6 \times 10^{-18} \, \text{J} $, $ m = 9.1 \times 10^{-31} \, \text{kg} $, $ q = 1.6 \times 10^{-19} \, \text{C} $, and $ B = 10^{-4} \, \text{T} $, the radius calculates to approximately 12 cm.

A \( 10 \, \text{eV} \) electron is circulating in a plane at right angles to a uniform field at magnetic induction \( 10^{-4} \, \text{Wb/m}^2 \) (\( = 1.0 \, \text{gauss} \)). The orbital radius of the electron is

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