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A square loop ABCD carrying a current i, is placed near and coplanar with a long straight conductor XY carrying a current I, the net force on the loop will be:
- 2μ₀Ii/3π
- μ₀Ii/2π
- 2μ₀Ii/3π
- μ₀Ii/2π
Correct answer: μ₀Ii/2π
Solution
The net force on the square loop is calculated by considering the forces on each side due to the magnetic field created by the long straight conductor. The forces on opposite sides of the loop cancel out partially, leaving a net force proportional to μ₀Ii/2π.
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