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Magnetic field intensity at the centre of a coil of 500 turns, radius 0.5 m and carrying a current of 2 A is
- 0.5 × 10⁻⁵ T
- 1.25 × 10⁻⁴ T
- 3 × 10⁻⁵ T
- 4 × 10⁻⁵ T
Correct answer: 1.25 × 10⁻⁴ T
Solution
The magnetic field at the center of a circular coil is given by B = (μ₀ * N * I) / (2 * R). Substituting μ₀ = 4π × 10⁻⁷ T·m/A, N = 500, I = 2 A, and R = 0.5 m, we get B = (4π × 10⁻⁷ * 500 * 2) / (2 * 0.5) = 1.25 × 10⁻⁴ T.
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