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A straight conductor carrying current i splits into two parts as shown in the figure. The radius of the circular loop is R. The total magnetic field at the centre P of the loop is:
- μ₀i / 2R , inward
- Zero
- 3μ₀i / 32R , outward
- 3μ₀i / 32R , inward
Correct answer: 3μ₀i / 32R , inward
Solution
The magnetic field at the center of the loop is calculated by summing the contributions from the circular arc and the straight segments. The net field is 3μ₀i / 32R, directed inward due to the right-hand rule.
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