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Since ϕtotal = ϕA + ϕB + ϕC = q / ε₀, let us assume flux linked with the plane surfaces A and C be ϕA = ϕC = ϕ'. Therefore, q / ε₀ = 2ϕ' + ϕB = 2ϕ' + ϕ. Find ϕ.
- ϕ = q / ε₀
- ϕ = q / 2ε₀
- ϕ = q / 4ε₀
- ϕ = q / 6ε₀
Correct answer: ϕ = q / 2ε₀
Solution
From the given equation, q/ε₀ = 2ϕ' + ϕ. Since ϕA = ϕC = ϕ', we can substitute ϕ' = ϕ/2 into the equation. Simplifying, we get ϕ = q / 2ε₀.
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