Exams › NEET › Physics

The unit of permittivity of free space, ε₀, is:

1. Coulomb²/(Newton-metre²)
2. Coulomb/Newton-metre²
3. Newton-metre²/Coulomb²
4. Coulomb²/Newton-metre²

Correct answer: Coulomb²/(Newton-metre²)

Solution

The unit of permittivity of free space, ε₀, is derived from Coulomb's law, where force is proportional to the product of charges divided by the square of the distance. Rearranging the formula gives ε₀'s unit as Coulomb²/(Newton-metre²).

Related NEET Physics questions

• A Gaussian surface in the figure is shown by dotted line. The electric field on the surface will be:
• The acceleration of a charged particle in a uniform electric field is : (where specific charge of a particle \( \left.=\frac{q}{m}\right) \)
• Two identical charged spheres suspended from a common point by two massless strings of lengths l, are initially at a distance d (d << l) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity v. Then v varies as a function of the distance x between the spheres, as:
• Suppose the charge of a proton and an electron differ slightly. One of them is −e, the other is (e + Δe). If the net electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then Δe is of the order of [Given mass of hydrogen mₕ = 1.67 × 10⁻²⁷ kg]:
• Two point charges A and B, having charges +Q and −Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes:
• Two parallel infinite line charges with linear charge densities +λ C/m and -λ C/m are placed at a distance of 2R in free space. What is the electric field mid-way between the two line charges?

⚔️ Practice NEET Physics free + battle 1v1 →