A Gaussian surface in the figure is shown by dotted line. The electric field on the surface will be:

due to \( q_{1} \) and \( q_{2} \) only
due to \( q_{2} \) only
zero
due to all

Correct answer: due to all

Solution

The electric field at any point on the Gaussian surface is the vector sum of contributions from all charges in the region. Gauss’s law relates the net flux through the surface to enclosed charge, but it does not mean only enclosed charges create the field on the surface.

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