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Charge (q) = 0.2 C; Distance (d) = 2 m; Angle θ = 60° and work done (W) = 4 J. Work done in moving the charge (W) = F·d cos θ = qEd cos θ. Find the electric field (E).

1. 20 N/C
2. 15 N/C
3. 10 N/C
4. 5 N/C

Correct answer: 10 N/C

Solution

The formula for work done is W = qEd cos θ. Substituting the given values: 4 = 0.2 × E × 2 × cos 60°. Since cos 60° = 0.5, we get 4 = 0.2 × E × 2 × 0.5. Solving for E, E = 10 N/C.

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