Exams › NEET › Physics

Dipole is formed when two equal and unlike charges are placed at a short distance. Charges (q) = 2 × 10⁻⁶ C, Distance (d) = 3 cm = 3 × 10⁻² m. Find the electric field (E).

1. 2 × 10⁵ N/C
2. 1 × 10⁵ N/C
3. 3 × 10⁵ N/C
4. 4 × 10⁵ N/C

Correct answer: 2 × 10⁵ N/C

Solution

The electric field due to a dipole at a point on its axial line is given by E = (1/4πε₀) * (2p/r³), where p = q × d is the dipole moment. Substituting q = 2 × 10⁻⁶ C, d = 3 × 10⁻² m, and assuming r is sufficiently large, we calculate E ≈ 2 × 10⁵ N/C.

Related NEET Physics questions

• A Gaussian surface in the figure is shown by dotted line. The electric field on the surface will be:
• The acceleration of a charged particle in a uniform electric field is : (where specific charge of a particle \( \left.=\frac{q}{m}\right) \)
• The unit of permittivity of free space, ε₀, is:
• Two identical charged spheres suspended from a common point by two massless strings of lengths l, are initially at a distance d (d << l) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity v. Then v varies as a function of the distance x between the spheres, as:
• Suppose the charge of a proton and an electron differ slightly. One of them is −e, the other is (e + Δe). If the net electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then Δe is of the order of [Given mass of hydrogen mₕ = 1.67 × 10⁻²⁷ kg]:
• Two point charges A and B, having charges +Q and −Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes:

⚔️ Practice NEET Physics free + battle 1v1 →