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ExamsNEETPhysics

Given: Electric field (E) = 500 V/m and potential difference (V) = 3000 V. We know that electric field (E) = V/d. Find the distance (d) between point charge and A.

  1. 6 m
  2. 5 m
  3. 4 m
  4. 3 m

Correct answer: 5 m

Solution

Using the formula E = V/d, rearrange to find d = V/E. Substituting V = 3000 V and E = 500 V/m, we get d = 3000/500 = 6 m.

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