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The electric intensity due to a dipole of length 10 cm and having a charge of 500 μC, at a point on the axis at a distance 20 cm from one of the charges in air, is

1. 6.25 × 10⁷ N/C
2. 9.28 × 10⁷ N/C
3. 13.1 × 10¹¹ N/C
4. 20.5 × 10⁷ N/C

Correct answer: 6.25 × 10⁷ N/C

Solution

The electric field due to a dipole on its axis is calculated using the formula E = (1/4πε₀) * (2p/r³), where p = q × d is the dipole moment. Substituting q = 500 μC, d = 10 cm, and r = 20 cm, the result is approximately 6.25 × 10⁷ N/C.

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