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In air, F_air = q1q2 / (4πε₀r²). In medium, F_m = q1q2 / (4πε₀Kr²).
- F_m / F_air = 1 / K
- F_m = F_air / K
- F_m decreases K-times
- None of the above
Correct answer: F_m / F_air = 1 / K
Solution
The force between charges in a medium is reduced by a factor of the dielectric constant (K) compared to air. Thus, the ratio F_m / F_air = 1 / K.
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