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From a point charge, there is a fixed point A. At A, there is an electric field of 500 V/m and potential difference of 3000 V. Distance between point charge and A will be
- 6m
- 8m
- 12m
- 16m
Correct answer: 6m
Solution
The relationship between electric field (E) and potential (V) for a point charge is given by E = V/r, where r is the distance. Rearranging, r = V/E = 3000/500 = 6 m.
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