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Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of repulsion between them, the number of electrons missing from each ion will be (e being the charge of an electron):
- 4πε₀Fd² / e²
- 4πε₀Fe² / d²
- 4πε₀Fd² / e
- 4πε₀Fd² / q²
Correct answer: 4πε₀Fd² / e²
Solution
The force between two charges is given by Coulomb's law: F = (1 / 4πε₀) * (q² / d²). Rearranging for q, we get q = √(4πε₀Fd²). Since q = ne (where n is the number of missing electrons), n = q / e = (4πε₀Fd²) / e².
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