Exams › NEET › Physics

Let 'n' be the degree of freedom γ = Cp / Cv = (n/2 + 1) R / (n/2) R = (1 + 2/n)

1. Cp = (n/2 + 1) R
2. Cv = (n/2) R
3. γ = Cp / Cv
4. γ = (1 + 2/n)

Correct answer: γ = (1 + 2/n)

Solution

The given equation γ = (1 + 2/n) directly matches option D, which is the expression for the ratio of specific heats in terms of degrees of freedom.

Related NEET Physics questions

• The molar specific heats of an ideal gas at constant pressure and volume are denoted by Cp and Cv, respectively. If γ = Cp / Cv and R is the universal gas constant, then Cv is equal to
• If γ be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is
• The number of translational degrees of freedom for a diatomic gas is
• What happens to the average velocity of gas molecules as temperature increases?
• The degree of freedom of a molecule of a triatomic gas is
• What is the formula for internal energy (U) of an ideal gas?

⚔️ Practice NEET Physics free + battle 1v1 →