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If γ be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is

1. 25 / (γ − 1)
2. 3 γ − 1
3. 2 / γ − 1
4. 9 / (γ − 1)

Correct answer: 9 / (γ − 1)

Solution

The degrees of freedom (f) of a gas molecule are related to the ratio of specific heats (γ) by the formula γ = (f + 2) / f. Rearranging this, f = 2 / (γ - 1). Substituting the options, only D matches correctly.

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