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The equation of state, corresponding to 8g of O₂ is

1. PV = 8 RT
2. PV = RT/4
3. PV = RT
4. PV = RT/2

Correct answer: PV = RT/2

Solution

The molar mass of O₂ is 32 g/mol. For 8 g of O₂, the number of moles is 8/32 = 1/4. The ideal gas equation is PV = nRT, so substituting n = 1/4 gives PV = RT/4.

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