Exams › NEET › Physics

The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be

1. PV = (5/16) RT
2. PV = (5/32) RT
3. PV = 5 RT
4. PV = (5/2) RT (where R is the gas constant)

Correct answer: PV = (5/32) RT

Solution

The molar mass of oxygen (O2) is 32 g/mol. For 5 g of oxygen, the number of moles (n) is 5/32. Using the ideal gas equation PV = nRT, substituting n = 5/32 gives PV = (5/32)RT.

Related NEET Physics questions

• The molar specific heats of an ideal gas at constant pressure and volume are denoted by Cp and Cv, respectively. If γ = Cp / Cv and R is the universal gas constant, then Cv is equal to
• If γ be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is
• The number of translational degrees of freedom for a diatomic gas is
• What happens to the average velocity of gas molecules as temperature increases?
• The degree of freedom of a molecule of a triatomic gas is
• What is the formula for internal energy (U) of an ideal gas?

⚔️ Practice NEET Physics free + battle 1v1 →