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At 10°C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110°C this ratio is:

1. x
2. 383/283 x
3. 10/110 x
4. 283/383 x

Correct answer: 383/283 x

Solution

For an ideal gas, the density divided by pressure is inversely proportional to temperature (in Kelvin). Converting temperatures to Kelvin: 10°C = 283 K and 110°C = 383 K. The ratio at 110°C becomes (283/383) times the original ratio, so the answer is (383/283)x.

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