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When volume of system is increased twice and temperature is decreased half of its initial temperature, then pressure becomes
- 2 times
- 4 times
- 1/2 times
- 1/4 times
Correct answer: 1/4 times
Solution
Using the ideal gas law, PV = nRT, if the volume is doubled (V → 2V) and the temperature is halved (T → T/2), the pressure P becomes P → P/4. Hence, the pressure becomes 1/4 times its initial value.
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