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A transistor-oscillator using a resonant circuit with an inductor L (of negligible resistance) and a capacitor C in series produce oscillations of frequency f. If L is doubled and C is changed to 4C, the frequency will be
- 8f
- f / 2√2
- f / 2
- f / 4
Correct answer: f / 2√2
Solution
The frequency of oscillation for an LC circuit is given by f = 1 / (2π√(LC)). If L is doubled and C is changed to 4C, the new frequency becomes f' = 1 / (2π√(2L × 4C)) = 1 / (2π√(8LC)) = f / 2√2.
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