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A galvanometer having a resistance of 8 ohms is shunted by a wire of resistance 2 ohms. If the total current is 1 amp, the part of it passing through the shunt will be
- 0.25 amp
- 0.2 amp
- 0.5 amp
- 0.5 amp
Correct answer: 0.5 amp
Solution
The current through the shunt is calculated using the current division rule. Since the shunt resistance is 2 ohms and the galvanometer resistance is 8 ohms, the current through the shunt is (8 / (8 + 2)) × 1 = 0.8 × 1 = 0.8 A. Thus, the correct answer is 0.8 A.
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