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A charge Q μC is placed at the centre of a cube, the flux coming out from any surface will be
- Q / 6ε₀ × 10⁻⁶
- Q / 6ε₀ × 10⁻³
- Q / 24ε₀
- Q / 8ε₀
Correct answer: Q / 6ε₀ × 10⁻⁶
Solution
By Gauss's law, the total flux through a closed surface is given by Φ = Q/ε₀. Since the charge is symmetrically placed at the center of the cube, the flux is equally distributed among its six faces. Thus, the flux through one face is Φ_face = Q / (6ε₀). Converting Q from μC to C introduces a factor of 10⁻⁶, giving the result as Q / 6ε₀ × 10⁻⁶.
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