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What is the escape velocity of oxygen molecules at temperature T?

1. V_escape = 11200 m/s
2. V_escape = √(3k_BT/m_0)
3. V_escape = 200 m/s
4. V_escape = √(400/300)

Correct answer: V_escape = √(3k_BT/m_0)

Solution

Escape velocity is the minimum velocity required for a molecule to escape Earth's gravitational field. The formula √(3k_BT/m_0) relates the root mean square speed of gas molecules to temperature, which is relevant to the context of molecular escape.

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