Exams › NEET › Physics

At a certain location, the strength of the electric field is \( 30.0 N / C . \) A charge of \( 3.00 C \) is placed at this location. How much force does this charge experience due to the electric field?

1. \( 90.0 N \) n
2. \( 10.0 N \)
3. \( 0.100 N \)
4. \( 270 N / C \) E . \( 3.33 N / C \)

Correct answer: \( 90.0 N \) n

Solution

The electric force on a charge in an electric field is given by F = qE. Substituting q = 3.00 C and E = 30.0 N/C gives F = 90.0 N.

Related NEET Physics questions

• Which of the following statements is not true about Gauss's law?
• A positive charge and a negative charge are held in place and initially form a dipole. Then a uncharged conducting bar is placed in between them. How is the force between the charges affected?
• The capacity of a parallel plate condenser is \( 10 \mu F \) without the dielectric. Material with a dielectric constant of 2 is used to fill half- thickness between the plates. The new capacitance is \( \mu F \)
• A point charge is brought in an electric field. The electric field at a nearby point: This question has multiple correct options
• Assertion A capacitor can be given only a limited quantity of charge Reason A capacitor is an arrangement which can store sufficient quantity of charge
• A soap bubble of radius \( 3 \mathrm{cm} \) is charged with surface charge density \( \sigma \) such that \( \frac{\sigma^{2}}{\epsilon_{0}}=0.4 S I \) units. The excess pressure inside the bubble in SI unit (surface tension of soap solution \( =3 \times \) \( 10^{-3} \mathrm{N} / \mathrm{m} \) ) is:

⚔️ Practice NEET Physics free + battle 1v1 →