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The capacity of a parallel plate condenser is \( 10 \mu F \) without the dielectric. Material with a dielectric constant of 2 is used to fill half- thickness between the plates. The new capacitance is \( \mu F \)

1. 10
2. 20
3. 15
4. 13.33

Correct answer: 15

Solution

When a dielectric fills only half the separation, the plate gap behaves like two capacitors in series: one with air and one with dielectric. Since the dielectric constant is 2 and each layer has half the thickness, the equivalent capacitance becomes 15 μF.

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