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Equation of motion of a body is \( \frac{\boldsymbol{d v}}{\boldsymbol{d t}}= \) \( 6-3 v, \) where \( v \) is the velocity in \( m s^{-1} \) and \( t \) is the time in second. Assuming particle at rest initially. Then This question has multiple correct options
- velocity of the body when its acceleration is zero is \( 2 m s^{-1} \)
- initial acceleration of the body is \( 6 m / s^{2} \)
- the velocity of the body when the acceleration is half the initial value is \( 1 \mathrm{m} / \mathrm{s} \)
- the body has a uniform acceleration
Correct answer: initial acceleration of the body is \( 6 m / s^{2} \)
Solution
At the instant the particle starts from rest, v = 0. Substituting into dv/dt = 6 - 3v gives acceleration = 6 m/s², so the initial acceleration statement is correct. The acceleration is not uniform because it depends on v, which changes with time.
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