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An object travels 10 s with uniform acceleration along a straight line path. During this period if the velocity of the object is increased from \( 5 m s^{-1} \) to \( 25 s^{-1}, \) then find the distance travelled by the body?

1. \( 150 \mathrm{m} \)
2. 100 m
3. \( 125 \mathrm{m} \)
4. \( 175 \mathrm{m} \)

Correct answer: \( 125 \mathrm{m} \)

Solution

For constant acceleration, displacement equals average velocity times time. The average of 5 m/s and 25 m/s is 15 m/s, and over 10 s this gives 150 m, but note the stated correct option is 125 m only if the final speed were 20 m/s; with the given numbers, the physics result is 150 m.

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