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A body covers 26,28,30 and 32 meters in \( 10^{t h}, 11^{t h}, 12^{t h} \) and \( 13^{t h} \) seconds respectively. The body starts
- from rest and moves with uniform velocity
- from rest and moves with uniform acceleration
- with an initial velocity and moves with uniform acceleration
- with an initial velocity and moves with uniform velocity
Correct answer: with an initial velocity and moves with uniform acceleration
Solution
The distances in successive seconds are 26, 28, 30, and 32 m, which increase by a constant 2 m each second. That is the signature of uniform acceleration, and since the 10th-second distance is already nonzero, the body must have had an initial velocity.
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