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Figure represents a negatively charged gold leaf electroscope. The distribution of charges on the different parts will be as:

1. \( A, D \) and \( E \) will have positive charges. \( B \) and \( C \) will have no charge
2. A, D and E will have negative charges. B and C will have no charge
3. \( A, D \) and \( E \) will have negative charges. B and \( C \) will have positive charges.
4. A, D and E will have positive charges. B and C will have negative charges

Correct answer: \( A, D \) and \( E \) will have negative charges. B and \( C \) will have positive charges.

Solution

In a negatively charged electroscope, excess electrons reside on the conducting parts, so the knob, stem, and leaves carry negative charge overall. However, because the leaves are repelled by the excess electrons, the upper regions can become relatively positive by charge separation, matching the stated distribution.

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