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Eight dipoles of charges of magnitude $e$ are placed inside a cube. The total electric flux coming out of the cube will be

1. $\frac{8e}{\epsilon_0}$
2. $\frac{16e}{\epsilon_0}$
3. $\frac{e}{\epsilon_0}$
4. Zero

Correct answer: Zero

Solution

Each dipole has equal and opposite charges, so the net charge of every dipole is zero. Therefore, the total enclosed charge inside the cube is zero, and by Gauss's law the net flux through the cube is zero.

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