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Charges $q$, $q$, and $-2q$ are placed at the corners of an equilateral triangle $ABC$ of side $l$. The magnitude of the electric dipole moment of the system is
- $ql$
- $2ql$
- $3ql$
- $4ql$
Correct answer: $3ql$
Solution
For a neutral system, the dipole moment is the vector sum $\vec p = \sum q_i \vec r_i$. Taking coordinates for the equilateral triangle and adding the contributions gives a resultant magnitude of $3ql$.
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