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When a charge of 3 coulombs is placed in a uniform electric field, it experiences a force of 3000 N. Within this field, the potential difference between two points separated by a distance of 1 cm is

1. 10 volts
2. 90 volts
3. 1000 volts
4. 3000 volts

Correct answer: 10 volts

Solution

The electric field is given by E = F/q = 3000/3 = 1000 N/C. For a separation of 1 cm = 0.01 m along the field, the potential difference is V = Ed = 1000 × 0.01 = 10 V.

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