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A particle has a mass 400 times that of the electron and a charge twice that of an electron. It is accelerated through a potential difference of 5 V. If the particle was initially at rest, its final kinetic energy will be

1. 5 eV
2. 10 eV
3. 100 eV
4. 2000 eV

Correct answer: 10 eV

Solution

The gain in kinetic energy of a particle accelerated through a potential difference is $K=qV$. Here the charge is twice the electron charge, so $q=2e$. Therefore $K=2e\times 5\,\text{V}=10\,\text{eV}$. The mass does not affect the energy gained.

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