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The radius of a soap bubble whose potential is 16 V is doubled. The new potential of the bubble will be

1. 2 V
2. 4 V
3. 8 V
4. 16 V

Correct answer: 8 V

Solution

A soap bubble behaves like a charged spherical conductor, for which potential is $V\propto \frac{1}{R}$. When the radius is doubled, the potential becomes half of 16 V. So the new potential is 8 V.

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