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When a proton is accelerated through 1 V, its kinetic energy will be

1. 1840 eV
2. 13.6 eV
3. 1 eV
4. 0.54 eV

Correct answer: 1 eV

Solution

The kinetic energy gained by a charge moving through a potential difference \(V\) is \(qV\). For a proton, \(q = e\), so through 1 V it gains energy \(e \times 1\,\text{V} = 1\,\text{eV}\).

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