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Two plates are 2 cm apart. A potential difference of 10 V is applied between them. The electric field between the plates is

1. 20 N/C
2. 500 N/C
3. 5 N/C
4. 250 N/C

Correct answer: 500 N/C

Solution

For a uniform field between parallel plates, \(E = V/d\). Here \(V = 10\,\text{V}\) and \(d = 2\,\text{cm} = 0.02\,\text{m}\). So \(E = 10/0.02 = 500\,\text{N/C}\).

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