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A body has a charge of $-80\,\mu\text{C}$. The number of additional electrons in it will be:
- $5\times10^8$
- $80\times10^{17}$
- $5\times10^{14}$
- $10^{17}$
Correct answer: $5\times10^{14}$
Solution
The number of excess electrons is $n = \dfrac{|Q|}{e}$. Here $|Q| = 80\times10^{-6}$ C, so $n = \dfrac{80\times10^{-6}}{1.6\times10^{-19}} = 5\times10^{14}$.
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