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Three capacitors of capacitances C_1, C_2, and C_3 are connected in series. Their total capacitance is

1. C_1 + C_2 + C_3
2. 1/(C_1 + C_2 + C_3)
3. 1/(1/C_1 + 1/C_2 + 1/C_3)
4. None of these

Correct answer: 1/(1/C_1 + 1/C_2 + 1/C_3)

Solution

For capacitors connected in series, the charge on each is the same and the total potential difference is the sum of individual potential differences. This leads to the reciprocal addition formula for equivalent capacitance.

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