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A capacitor of capacitance $C$ is charged to a potential $V$. The energy stored in it is:
- $CV^2$
- $\frac{1}{2}CV^2$
- $CV$
- $\frac{1}{2}VC^2$
Correct answer: $\frac{1}{2}CV^2$
Solution
The energy stored in a capacitor is given by $U=\frac{1}{2}CV^2$. This comes from the work done in charging the capacitor gradually from zero to $V$.
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