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A capacitor of capacitance $50\,\mu\text{F}$ is charged to $10\,\text{V}$. What is the energy stored in it?

1. $2.5 \times 10^{-3}\,\text{J}$
2. $2.5 \times 10^{-4}\,\text{J}$
3. $5 \times 10^{-2}\,\text{J}$
4. $1.2 \times 10^{-8}\,\text{J}$

Correct answer: $2.5 \times 10^{-3}\,\text{J}$

Solution

Using $U=\frac{1}{2}CV^2$, we get $U=\frac{1}{2}\times 50\times10^{-6}\times 10^2$. This equals $2.5\times10^{-3}\,\text{J}$.

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