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If $n$ capacitors are connected in parallel to a source of voltage $V$, then the energy stored is

1. $CV$
2. $\frac12 nCV^2$
3. $2CV$
4. $\frac12 CV^2n$

Correct answer: $\frac12 nCV^2$

Solution

For $n$ identical capacitors in parallel, the equivalent capacitance is $C_{\text{eq}}=nC$. The stored energy is $U=\frac12 C_{\text{eq}}V^2=\frac12 nCV^2$.

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