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The energy stored in the condenser is
- $QV$
- $\frac{1}{2}QV$
- $\frac{1}{2}C$
- $\frac{1}{2}CQ$
Correct answer: $\frac{1}{2}QV$
Solution
The energy stored in a capacitor is $U=\frac{1}{2}CV^2$. Since $Q=CV$, this can also be written as $U=\frac{1}{2}QV$. Thus the correct option is $\frac{1}{2}QV$.
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