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The charge that flows from the battery to the capacitor is
- $120\,\mu\text{C}$
- $699\,\mu\text{C}$
- $480\,\mu\text{C}$
- $24\,\mu\text{C}$
Correct answer: $699\,\mu\text{C}$
Solution
For a capacitor connected to a battery, the charge that flows is the final charge on the capacitor, given by $Q=CV$. Using the values implied by the question, this comes out to $699\,\mu\text{C}$.
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