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The moment of inertia of a flywheel is \( 0.2 k g m^{2} \) which is initially stationary. constant external torque \( 5 N m \) acts on the wheel. The work done by this torque during 10 sec is:

1. \( 1250 J \)
2. \( 2500 J \)
3. \( 5000 J \)
4. \( 6250 J \)

Correct answer: \( 1250 J \)

Solution

A constant torque produces a constant angular acceleration, so the wheel’s angular displacement in 10 s can be found from rotational motion equations. The work done by the torque is then W = τθ, which gives 1250 J.

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