Exams › NEET › Physics
The magnetic field produced by a current I in a coil is B₁ = μ₀I/2R, and the field produced by a current 2I in the same coil is B₂ = μ₀(2I)/2R. The combined magnetic field, Bnet, is determined using the formula Bnet = √(B₁² + B₂² + 2B₁B₂ cosθ), where θ is 90°. What is the value of Bnet?
- Bnet = √(B₁² + B₂² + 2B₁B₂ cosθ)
- Bnet = √(B₁² + B₂²)
- Bnet = √5μ₀I/2R
- None of these
Correct answer: Bnet = √(B₁² + B₂²)
Solution
Since θ = 90°, cosθ = 0. Substituting this into the formula, Bnet = √(B₁² + B₂²). This matches option B.
Related NEET Physics questions
- An alternating electric field, of frequency ν, is applied across the dees (radius = R) of a cyclotron that is being used to accelerate protons (mass = m). The operating magnetic field (B) used in the cyclotron and the kinetic energy (K) of the proton beam, produced by it, are given by:
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in uniform magnetic field. What should be the energy of an α-particle to describe a circle of same radius in the same field?
- A positively charged particle moving due east enters a region of uniform magnetic field directed vertically upwards. The particle will
- An electron enters a region where magnetic field (\( \vec{B} \)) and electric field (\( \vec{E} \)) are mutually perpendicular, then
- A \( 10 \, \text{eV} \) electron is circulating in a plane at right angles to a uniform field at magnetic induction \( 10^{-4} \, \text{Wb/m}^2 \) (\( = 1.0 \, \text{gauss} \)). The orbital radius of the electron is
- A uniform magnetic field acts at right angles to the direction of motion of an electron. As a result, the electron moves in a circular path of radius \( 2 \, \text{cm} \). If the speed of electron is doubled, then the radius of the circular path will be
⚔️ Practice NEET Physics free + battle 1v1 →