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In case of full wave rectifier, Fundamental frequency = 2 × mains frequency = 2 × 50 = 100Hz.

1. (a) In case of full wave rectifier, Fundamental frequency = 2 × mains frequency = 2 × 50 = 100Hz.
2. (b) Barrier potential does not depend on diode design. Barrier potential depends upon temperature, doping density, and forward biasing.
3. (c) Barrier potential depends on diode design.
4. (d) None of the above.

Correct answer: (a) In case of full wave rectifier, Fundamental frequency = 2 × mains frequency = 2 × 50 = 100Hz.

Solution

In a full-wave rectifier, the output frequency is twice the mains frequency because both the positive and negative halves of the AC waveform are rectified. Hence, the fundamental frequency is 2 × 50 Hz = 100 Hz.

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