Exams › NEET › Physics

The transfer ratio β of a transistor is 50. The input resistance of the transistor when used in the common emitter configuration is 1 kΩ. The peak value of the collector A.C. current for an A.C. input voltage of 0.01 V peak is

1. 100 μA
2. 0.01 mA
3. 0.25 mA
4. 500 μA

Correct answer: 500 μA

Solution

The current gain β relates the collector current (Ic) to the base current (Ib) as Ic = β × Ib. The base current is given by Ib = Vin / Rin, where Vin = 0.01 V and Rin = 1 kΩ. Substituting, Ib = 0.01 / 1000 = 10 μA. Therefore, Ic = 50 × 10 μA = 500 μA.

Related NEET Physics questions

• Which of the following is unipolar transistor?
• Band gap in a semiconductor is of the order
• The transistor are usually made of
• Electric conduction in a semiconductor takes place due to
• The energy band diagrams for three semiconductor sample of silicon are shown. It follows that.
• A pure semiconductor at absolute zero has

⚔️ Practice NEET Physics free + battle 1v1 →