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A transistor is operated in common-emitter configuration at Vc = 2 V such that a change in the base current from 100 μA to 200 μA produces a change in the collector current from 5 mA to 10 mA. The current gain is

1. 100
2. 150
3. 50
4. 75

Correct answer: 50

Solution

The current gain (β) in a common-emitter configuration is given by β = ΔIc / ΔIb. Here, ΔIc = 10 mA - 5 mA = 5 mA and ΔIb = 200 μA - 100 μA = 100 μA. Converting units, β = (5 × 10^-3) / (100 × 10^-6) = 50.

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