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A transistor is operated in common emitter configuration at Vc = 2V such that a change in the base current from 100 μA to 300 μA produces a change in the collector current from 10mA to 20mA. The current gain is:
- 50
- 75
- 100
- 25
Correct answer: 50
Solution
The current gain (β) in a common emitter configuration is given by β = ΔIc / ΔIb. Here, ΔIc = 20mA - 10mA = 10mA = 10 × 10⁻³ A, and ΔIb = 300μA - 100μA = 200μA = 200 × 10⁻⁶ A. Substituting, β = (10 × 10⁻³) / (200 × 10⁻⁶) = 50.
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